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# Runtime: 65 ms (Top 24.05%) | Memory: 13.9 MB (Top 50.57%)
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class Solution:
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    def validSquare(self, p1, p2, p3, p4):
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        def cal(A, B):
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            return abs(A[0] - B[0]) + abs(A[1] - B[1])
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        d = [
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            cal(p1, p2),
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            cal(p1, p3),
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            cal(p1, p4),
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            cal(p2, p3),
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            cal(p2, p4),
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            cal(p3, p4),
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        ]
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        d.sort()
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        return 0 < d[0] == d[1] == d[2] == d[3] and d[4] == d[5]