1
impl Solution {
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pub fn is_anagram(s: String, t: String) -> bool {
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let mut map = std::collections::HashMap::new();
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s.chars().for_each(|c| *map.entry(c).or_insert(0) += 1);
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t.chars().for_each(|c| *map.entry(c).or_insert(0) -= 1);
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!map.into_values().any(|count| count != 0)
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}
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}

0

WPM •0 •0

100%

ACC •0 •0

0s

TIME •0