1class Solution {2public boolean isAnagram(String s, String t) {3if (s.length() != t.length()) return false;4int[] haha1 = new int[26]; // 26 because input contains of only lower english letters5int[] haha2 = new int[26];6for (int i = 0; i < s.length(); ++i) {7haha1[(int) s.charAt(i) - 97] += 1; // omitting 97 because 'a' is 97, it will be 0 now8haha2[(int) t.charAt(i) - 97] += 1;9}10for (int i = 0; i < haha1.length; ++i) {11if (haha1[i] != haha2[i]) return false;12}13return true;14}15}