2
public int maxTwoEvents(int[][] events) {3
Arrays.sort(events, (a, b) -> a[0] - b[0]);4
int onRight = 0, maxOne = 0, n = events.length;5
int[] rightMax = new int[n + 1];6
for (int i = n - 1; i >= 0; i--) {7
int start = events[i][0], end = events[i][1], val = events[i][2];8
maxOne = Math.max(val, maxOne);9
rightMax[i] = Math.max(rightMax[i + 1], val);12
for (int i = 0; i < n; i++) {13
int start = events[i][0], end = events[i][1], val = events[i][2];14
int idx = binarySearch(end, events);16
two = Math.max(rightMax[idx] + val, two);19
return Math.max(two, maxOne);22
public int binarySearch(int end, int[][] arr) {23
int left = 0, right = arr.length;24
while (left < right) {25
int mid = left + (right - left) / 2;26
if (arr[mid][0] > end) {