1
class Solution {
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public int maxTwoEvents(int[][] events) {
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Arrays.sort(events, (a, b) -> a[0] - b[0]);
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int onRight = 0, maxOne = 0, n = events.length;
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int[] rightMax = new int[n + 1];
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for (int i = n - 1; i >= 0; i--) {
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int start = events[i][0], end = events[i][1], val = events[i][2];
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maxOne = Math.max(val, maxOne);
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rightMax[i] = Math.max(rightMax[i + 1], val);
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}
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int two = 0;
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for (int i = 0; i < n; i++) {
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int start = events[i][0], end = events[i][1], val = events[i][2];
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int idx = binarySearch(end, events);
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if (idx < n) {
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two = Math.max(rightMax[idx] + val, two);
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}
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}
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return Math.max(two, maxOne);
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}
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public int binarySearch(int end, int[][] arr) {
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int left = 0, right = arr.length;
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while (left < right) {
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int mid = left + (right - left) / 2;
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if (arr[mid][0] > end) {
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right = mid;
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} else {
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left = mid + 1;
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}
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}
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return left;
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}
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}

0

WPM •0 •0

100%

ACC •0 •0

0s

TIME •0