1
class Solution {
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public int numberOfWeakCharacters(int[][] properties) {
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int[] maxH = new int[100002];
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int count = 0;
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for (int[] point : properties) {
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maxH[point[0]] = Math.max(point[1], maxH[point[0]]);
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}
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for (int i = 100000; i >= 0; i--) {
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maxH[i] = Math.max(maxH[i + 1], maxH[i]);
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}
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for (int[] point : properties) {
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if (point[1] < maxH[point[0] + 1]) count++;
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}
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return count;
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}
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}

0

WPM •0 •0

100%

ACC •0 •0

0s

TIME •0