1
class Solution:
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    def findErrorNums(self, nums):
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        n = len(nums)
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        v = [0] * (n + 1)
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        missing, duplicate = 0, 0
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        for num in nums:
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            v[num] += 1
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        for i in range(1, len(v)):
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            if v[i] == 2:
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                duplicate = i
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            if v[i] == 0:
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                missing = i
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        return [duplicate, missing]