1class Solution {2 public:3 int reverse(int x) {4 long res = 0;5 while (abs(x) > 0) {6 res = (res + x % 10) * 10;7 x /= 10;8 }9 x < 0 ? res = res / 10 *-1 : res = res / 10;10 if (res < INT32_MIN || res > INT32_MAX) {11 res = 0;12 }13 return res;14 }15};
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