3
vector<int> assignTasks(vector<int> &servers, vector<int> &tasks) {4
priority_queue<vector<long long>, vector<vector<long long>>, greater<vector<long long>>> free,6
for (int i = 0; i < servers.size(); ++i) {7
free.push(vector<long long>{servers[i], i});11
queue<int> task_queue;12
while (ans.size() < tasks.size()) {13
// Bring all eligible tasks to task_queue.14
for (int i = ans.size() + task_queue.size(); i <= time && i < tasks.size(); ++i) {15
task_queue.push(tasks[i]);17
// Bring all eligible servers to free queue.18
while (!busy.empty() && busy.top()[0] <= time) {19
auto &top = busy.top();20
free.push(vector<long long>{top[1], top[2]});23
// If we have no servers, we cannot match until one of the servers becomes29
while (!task_queue.empty() && !free.empty()) {30
// Now we just take the first task and first server as per defined31
// priority and match the two.32
int task = task_queue.front();33
auto &top = free.top();34
ans.push_back(top[1]);35
busy.push(vector<long long>{time + task, top[0], top[1]});39
// Only increment time to receive new tasks once we have processed all41
if (task_queue.empty()) time++;