1
class Solution:
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def orderlyQueue(self, s: str, k: int) -> str:
3
if k > 1:
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s = list(c for c in s)
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s.sort()
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return "".join(s)
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s1 = s
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for i in range(len(s)):
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s = s[1:] + s[0]
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s1 = min(s1, s)
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return s1

0

WPM •0 •0

100%

ACC •0 •0

0s

TIME •0