1class Solution:2 def numOfSubarrays(self, arr: List[int]) -> int:3 ce, co = 0, 04 s = 05 for x in arr:6 if x % 2 == 0:7 ce += 18 else:9 old_co = co10 co = ce + 111 ce = old_co1213 s += co1415 return s % (10**9 + 7)
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ACC •0 •0
TIME •0