Number of Students Doing Homework at a Given Time LeetCode solution in Python

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# Runtime: 67 ms (Top 36.82%) | Memory: 13.9 MB (Top 71.93%)
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class Solution(object):
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    def busyStudent(self, startTime, endTime, queryTime):
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        res = 0
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        for i in range(len(startTime)):
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            if startTime[i] <= queryTime <= endTime[i]:
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                res += 1
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            else:
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                pass
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        return res