1class Solution {2 public:3 int numOfStrings(vector<string> &patterns, string word) {4 int count = 0;5 for (int i = 0; i < patterns.size(); i++) {6 if (word.find(patterns[i]) != string::npos) count++;7 }8 return count;9 }10};
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ACC •0 •0
TIME •0