Number of People Aware of a Secret LeetCode solution in Python

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class Solution:
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    def peopleAwareOfSecret(self, n: int, delay: int, forget: int) -> int:
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        table = [0] * (forget + 1)
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        table[1] = 1
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        days = 1
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        while days <= n - 1:
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            count = 0
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            for k in range(forget - 1, -1, -1):
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                if k + 1 > delay:
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                    table[k + 1] = table[k]
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                    count += table[k]
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                elif k + 1 <= delay:
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                    table[k + 1] = table[k]
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            table[1] = count
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            days += 1
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        count = 0
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        for k in range(1, forget + 1):
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            count += table[k]
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        return count % (pow(10, 9) + 7)