Number of Excellent Pairs LeetCode solution in JavaScript

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var countExcellentPairs = function (nums, k) {
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  const map = new Map();
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  const set = new Set();
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  const l = nums.length;
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  let res = 0;
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  for (let num of nums) {
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    let temp = num.toString(2).split("1").length - 1;
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    if (!map.has(temp)) {
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      map.set(temp, new Set([num]));
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    } else {
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      map.get(temp).add(num);
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    }
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  }
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  for (let num of nums) {
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    let temp = num.toString(2).split("1").length - 1;
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    if (!set.has(num)) {
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      let gap = Math.max(0, k - temp);
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      for (let key of map.keys()) {
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        if (key >= gap) {
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          res += map.get(key).size;
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        }
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      }
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      set.add(num);
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    } else {
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      continue;
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    }
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  }
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  return res;
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};