Number of Burgers with No Waste of Ingredients LeetCode solution in Python

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class Solution(object):
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    def numOfBurgers(self, t, c):
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        if t == c == 0:
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            return [0, 0]
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        four = (t - 2 * c) // 2  # no of jumbo burgers by solving 4x+2y=t and x+y=c
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        two = c - four  # number of small burgers
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        if (
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            c >= t or (t - 2 * c) % 2 == 1 or four < 0 or two < 0
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        ):  # if cheese is less than tomatoes or if number of jumbo burgers is a decimal or number of burgers are negtive we return empty list
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            return []
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        return [four, two]