Number of Burgers with No Waste of Ingredients LeetCode solution in JavaScript

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/**
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 * @param {number} tomatoSlices
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 * @param {number} cheeseSlices
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 * @return {number[]}
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 */
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var numOfBurgers = function (tomatoSlices, cheeseSlices) {
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  if (tomatoSlices & 1) return []; // return [] if tomatoSlices is odd
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  const j = (tomatoSlices >> 1) - cheeseSlices; // jumbo = (tomatoSlices / 2) - cheeseSlices
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  return j < 0 || j > cheeseSlices ? [] : [j, cheeseSlices - j]; // small = cheeseSlices - jumbo, if any of jmbo and small < 0 return [] otherwise return [jumbo, small]
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};