N-Repeated Element in Size 2N Array LeetCode solution in JavaScript

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var repeatedNTimes = function (nums) {
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  //   loop through the array and then as we go over every num we filter that number and get the length. If the length is equal to 1 that is not the element so we continue if its not equal to one its the element we want and we just return that element.
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  for (let num of nums) {
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    let len = nums.filter((element) => element === num).length;
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    if (len == 1) continue;
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    else return num;
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  }
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};