Minimum Suffix Flips LeetCode solution in JavaScript

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var minFlips = function (target) {
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target = "0" + target;
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let count = (target.match(/01/g) || []).length * 2;
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return target[target.length - 1] === "0" ? count : count - 1;
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};

0

WPM •0 •0

100%

ACC •0 •0

0s

TIME •0