Minimum Operations to Make Array Equal LeetCode solution in JavaScript

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var minOperations = function (n) {
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  let reqNum;
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  if (n % 2 != 0) {
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    reqNum = Math.floor(n / 2) * 2 + 1;
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  } else {
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    reqNum = (Math.floor(n / 2) * 2 + 1 + (Math.floor(n / 2) - 1) * 2 + 1) / 2;
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  }
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  let count = 0;
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  for (let i = 1; i < reqNum; i += 2) {
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    count += reqNum - i;
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  }
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  return count;
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};