Minimum Number of Operations to Convert Time LeetCode solution in JavaScript

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var getTime = function (time) {
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  var [hrs, mins] = time.split(":");
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  return parseInt(hrs) * 60 + parseInt(mins);
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};
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var convertTime = function (current, correct) {
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  var diff = getTime(correct) - getTime(current);
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  var order = [60, 15, 5, 1];
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  var ops = 0;
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  order.forEach((val) => {
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    ops += Math.floor(diff / val);
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    diff %= val;
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  });
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  return ops;
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};