Minimum Number of Operations to Convert Time LeetCode solution in C++

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class Solution {
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 public:
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  int HHMMToMinutes(string s) {
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    return stoi(s.substr(0, 2)) * 60 + stoi(s.substr(3, 2));
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  }
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  int convertTime(string current, string correct) {
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    int diff = -HHMMToMinutes(current) + HHMMToMinutes(correct);
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    vector<int> order = {60, 15, 5, 1};
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    int i = 0;
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    int ans = 0;
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    while (i < 4) {
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      ans += (diff / order[i]);
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      diff %= order[i];
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      i++;
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    }
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    return ans;
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  }
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};