Minimum Number of K Consecutive Bit Flips LeetCode solution in JavaScript

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var minKBitFlips = function (nums, k) {
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  let count = 0;
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  for (let i = 0; i < nums.length; i++) {
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    if (nums[i] == 0) {
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      for (let j = 0; j < k && i + k <= nums.length; j++) {
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        nums[i + j] = 1 - nums[i + j];
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      }
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      count++;
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    }
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  }
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  return nums.every((n) => n == 1) ? count : -1;
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};