Minimum Limit of Balls in a Bag LeetCode solution in JavaScript

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var minimumSize = function (nums, maxOperations) {
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  let i = 1;
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  let j = Math.max(...nums);
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  while (i <= j) {
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    let mid = Math.floor((j - i) / 2 + i);
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    let count = 0;
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    nums.forEach((n) => (count += Math.floor((n - 1) / mid)));
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    if (count <= maxOperations) {
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      j = mid - 1;
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    } else {
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      i = mid + 1;
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    }
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  }
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  return i;
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};