Minimum Flips to Make a OR b Equal to c LeetCode solution in JavaScript

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var minFlips = function (a, b, c) {
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  let ans = 0;
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  for (let bit = 0; bit < 32; bit++) {
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    let bit_a = (a >> bit) & 1,
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      bit_b = (b >> bit) & 1,
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      bit_c = (c >> bit) & 1;
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    if (bit_c !== (bit_a | bit_b)) {
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      if (bit_c === 1) {
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        //a b will be 0 0
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        ans += 1;
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      } else {
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        //a b -> 0 1 -> 1 0 -> 1 1
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        ans += bit_a + bit_b === 2 ? 2 : 1;
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      }
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    }
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  }
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  return ans;
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};