Minimum Flips to Make a OR b Equal to c LeetCode solution in Java

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class Solution {
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  public int minFlips(int a, int b, int c) {
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    int j = -1;
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    int x = a | b;
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    int count = 0;
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    while (c != 0 || x != 0) {
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      j++;
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      int aa = x % 2;
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      int bb = c % 2;
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      if (aa == 0 && bb == 1) count++;
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      else if (aa == 1 && bb == 0) count += funcount(j, a, b);
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      x = x >> 1;
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      c = c >> 1;
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    }
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    return count;
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  }
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  public static int funcount(int shift, int a, int b) {
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    int cc = 0;
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    int mask = 1 << shift;
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    int b1 = a & mask;
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    int b2 = b & mask;
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    if (b1 != 0) cc++;
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    if (b2 != 0) cc++;
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    return cc;
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  }
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}