Minimum Flips to Make a OR b Equal to c LeetCode solution in C++

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class Solution {
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 public:
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  int minFlips(int a, int b, int c) {
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    int changeBits = 0;
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    for (int i = 0; i < 32; i++) {
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      int lastBitA = 0;
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      int lastBitB = 0;
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      int lastBitC = 0;
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      if (((a >> i) & 1) == 1) {
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        lastBitA = 1;
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      }
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      if (((b >> i) & 1) == 1) {
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        lastBitB = 1;
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      }
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      if (((c >> i) & 1) == 1) {
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        lastBitC = 1;
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      }
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      if (lastBitC == 1) {
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        if (lastBitA == 0 & lastBitB == 0) {
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          changeBits++;
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        }
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      } else {
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        if (lastBitA == 1 || lastBitB == 1) {
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          if (lastBitA == 1) {
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            changeBits++;
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          }
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          if (lastBitB == 1) {
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            changeBits++;
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          }
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        }
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      }
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    }
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    return changeBits;
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  }
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};