Minimum Cost to Set Cooking Time LeetCode solution in JavaScript

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/**
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 * @param {number} startAt
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 * @param {number} moveCost
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 * @param {number} pushCost
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 * @param {number} targetSeconds
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 * @return {number}
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 */
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var minCostSetTime = function (startAt, moveCost, pushCost, targetSeconds) {
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  let cost = Infinity;
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  let maxMinutes = Math.floor(targetSeconds / 60);
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  for (let min = 0; min <= maxMinutes; min++) {
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    let secs = targetSeconds - min * 60;
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    if (secs > 99 || min > 99) continue;
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    let buttons = String(100 * min + secs);
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    let prev = Number(buttons[0]);
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    let sum = 0;
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    //start index will vary according to startAt pointer
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    let start = 0;
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    //If startAt is equal to first button, we need to add pushCost fatigue
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    if (prev === startAt) {
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      sum += pushCost;
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      start = 1;
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    } else {
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      //Else we need to add moveCost fatigue
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      sum += moveCost;
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    }
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    for (let i = start; i < buttons.length; i++) {
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      let button = Number(buttons[i]);
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      if (button !== prev) {
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        sum += moveCost + pushCost;
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      } else {
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        sum += pushCost;
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      }
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      prev = button;
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    }
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    cost = Math.min(cost, sum);
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  }
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  return cost;
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};