Minimum Bit Flips to Convert Number LeetCode solution in Python

1
class Solution:
2
    def minBitFlips(self, s: int, g: int) -> int:
3
        count = 0
4
        while s or g:
5
            if s % 2 != g % 2:
6
                count += 1
7
            s, g = s // 2, g // 2
8
        return count