Minimum Amount of Time to Fill Cups LeetCode solution in Python

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# Runtime: 42 ms (Top 62.11%) | Memory: 13.9 MB (Top 56.09%)
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class Solution:
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    def fillCups(self, amount: List[int]) -> int:
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        count = 0
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        amount = sorted(amount, reverse=True)
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        while amount[0] > 0:
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            amount[0] -= 1
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            amount[1] -= 1
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            count += 1
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            amount = sorted(amount, reverse=True)
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        return count