Minimize Deviation in Array LeetCode solution in JavaScript

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var minimumDeviation = function (nums) {
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  let pq = new MaxPriorityQueue({ priority: (x) => x });
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  for (let n of nums) {
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    if (n % 2) n *= 2;
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    pq.enqueue(n);
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  }
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  let ans = pq.front().element - pq.back().element;
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  while (pq.front().element % 2 === 0) {
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    pq.enqueue(pq.dequeue().element / 2);
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    ans = Math.min(ans, pq.front().element - pq.back().element);
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  }
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  return ans;
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};