Maximum XOR for Each Query LeetCode solution in JavaScript

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/**
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 * @param {number[]} nums
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 * @param {number} maximumBit
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 * @return {number[]}
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 */
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var getMaximumXor = function (nums, maximumBit) {
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  let xor = (1 << maximumBit) - 1;
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  for (let i = 0; i < nums.length; i++) {
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    xor ^= nums[i];
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    nums[i] = xor;
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  }
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  return nums.reverse();
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};