1class Solution {2 public int maxSubArray(int[] nums) {3 int n = nums.length;4 int currmax = 0;5 int gmax = nums[0];6 for (int i = 0; i < n; i++) {7 currmax += nums[i];8 gmax = Math.max(gmax, currmax);9 currmax = Math.max(currmax, 0);10 }11 return gmax;12 }13}
WPM •0 •0
ACC •0 •0
TIME •0