Maximum Number of Balloons LeetCode solution in Python

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class Solution:
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    def maxNumberOfBalloons(self, text: str) -> int:
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        freq = {"b": 0, "a": 0, "l": 0, "o": 0, "n": 0}
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        for char in text:
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            if not char in freq:
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                continue
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            step = 0.5 if char == "l" or char == "o" else 1
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            freq[char] += step
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        result = min(freq.values())
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        return floor(result)