Majority Element II LeetCode solution in JavaScript

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/**
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 * @param {number[]} nums
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 * @return {number[]}
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 */
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var majorityElement = function (nums) {
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  const objElement = {};
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  const timesVar = Math.floor(nums.length / 3);
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  const resultSet = new Set();
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  for (var indexI = 0; indexI < nums.length; indexI++) {
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    if (objElement[nums[indexI]]) {
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      objElement[nums[indexI]] = objElement[nums[indexI]] + 1;
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    } else objElement[nums[indexI]] = 1;
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    if (objElement[nums[indexI]] > timesVar) resultSet.add(nums[indexI]);
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  }
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  return [...resultSet];
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};