1class Solution:2 def longestSubsequence(self, s: str, k: int) -> int:34 end, n = len(s) - 1, s.count("0")5 while end >= 0 and int(s[end:], 2) <= k:6 end -= 17 return n + s[end + 1 :].count("1")
WPM •0 •0
ACC •0 •0
TIME •0