Long Pressed Name LeetCode solution in JavaScript

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var isLongPressedName = function (name, typed) {
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  let i = 0;
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  let j = 0;
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  while (j < typed.length) {
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    if (i < name.length && name[i] === typed[j]) i++;
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    else if (typed[j] !== typed[j - 1]) return false; // this needs when name is traversed but there is tail of characters in typed
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    j++; // Base case. keep going through typed anyway hitting first condition from time to time: (i < name.length && name[i] === typed[j])
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  }
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  return i === name.length;
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};