Long Pressed Name LeetCode solution in Java

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class Solution {
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  public boolean isLongPressedName(String name, String typed) {
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    int i = 0;
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    int j = 0;
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    int m = name.length();
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    int n = typed.length();
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    while (j < n) {
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      if (i < m && name.charAt(i) == typed.charAt(j)) {
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        i++;
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        j++;
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      } else if (j > 0 && typed.charAt(j) == typed.charAt(j - 1)) {
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        j++;
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      } else {
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        return false;
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      }
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    }
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    return i == m;
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  }
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}