Long Pressed Name LeetCode solution in C++

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class Solution {
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 public:
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  bool isLongPressedName(string name, string typed) {
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    int j = 0, i = 0;
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    for (; i < name.length() && j < typed.length(); i++) {
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      if (name[i] != typed[j++]) return false;
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      if (i < name.length() && name[i] != name[i + 1]) {
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        while (j < typed.length() && typed[j] == name[i]) j++;
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      }
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    }
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    return (i == name.length() && j == typed.length());
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  }
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};