Largest Plus Sign LeetCode solution in C++

1
class Solution {
2
public:
3
int orderOfLargestPlusSign(int n, vector<vector<int>> &mines) {
4
// jai shri ram
5
int ans = 0;
6
vector<bool> block(25 * int(1e4) + 1, 0);
7
vector<vector<int>> dp(n, vector<int>(n, 0));
8
for (auto x : mines) {
9
int a = x[0], b = x[1];
10
block[a * n + b] = true;
11
}
12
for (int i = 0; i < n; i++) {
13
int sum = 0;
14
for (int j = 0; j < n; j++) {
15
if (block[i * n + j]) {
16
sum = 0;
17
} else {
18
sum += 1;
19
}
20
dp[i][j] = sum;
21
}
22
}
23
for (int j = 0; j < n; j++) {
24
int sum = 0;
25
for (int i = 0; i < n; i++) {
26
if (block[i * n + j]) {
27
sum = 0;
28
} else
29
sum += 1;
30
dp[i][j] = min(dp[i][j], sum);
31
}
32
}
33
for (int j = n - 1; j >= 0; j--) {
34
int sum = 0;
35
for (int i = n - 1; i >= 0; i--) {
36
if (block[i * n + j]) {
37
sum = 0;
38
} else
39
sum += 1;
40
dp[i][j] = min(dp[i][j], sum);
41
}
42
}
43
for (int i = n - 1; i >= 0; i--) {
44
int sum = 0;
45
for (int j = n - 1; j >= 0; j--) {
46
if (block[i * n + j]) {
47
sum = 0;
48
} else
49
sum += 1;
50
dp[i][j] = min(dp[i][j], sum);
51
ans = max(ans, dp[i][j]);
52
}
53
}
54
return ans;
55
}
56
};

0

WPM •0 •0

100%

ACC •0 •0

0s

TIME •0