Largest Number At Least Twice of Others LeetCode solution in JavaScript

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/**
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 * @param {number[]} nums
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 * @return {number}
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 */
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var dominantIndex = function (nums) {
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  let first = -Infinity;
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  let second = -Infinity;
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  let ans = 0;
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  for (let i = 0; i < nums.length; i++) {
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    if (nums[i] > first) {
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      second = first;
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      first = nums[i];
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      ans = i;
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    } else if (nums[i] > second) {
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      second = nums[i];
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    }
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  }
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  return first >= second * 2 ? ans : -1;
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};