Largest Number At Least Twice of Others LeetCode solution in Java

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class Solution {
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  public int dominantIndex(int[] nums) {
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    if (nums == null || nums.length == 0) {
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      return -1;
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    }
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    if (nums.length == 1) {
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      return 0;
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    }
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    int max = Integer.MIN_VALUE + 1;
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    int secondMax = Integer.MIN_VALUE;
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    int index = 0;
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    for (int i = 0; i < nums.length; i++) {
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      if (nums[i] > max) {
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        secondMax = max;
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        max = nums[i];
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        index = i;
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      } else if (nums[i] != max && nums[i] > secondMax) {
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        secondMax = nums[i];
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      }
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    }
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    if (secondMax * 2 <= max) {
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      return index;
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    }
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    return -1;
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  }
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}