Largest Number At Least Twice of Others LeetCode solution in C++

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class Solution {
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 public:
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  int dominantIndex(vector<int> &nums) {
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    if (nums.size() < 2) {
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      return nums.size() - 1;
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    }
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    int max1 = INT_MIN;
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    int max2 = INT_MIN;
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    int result = -1;
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    for (int i = 0; i < nums.size(); i++) {
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      if (nums[i] > max1) {
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        result = i;
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        max2 = max1;
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        max1 = nums[i];
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      } else if (nums[i] > max2) {
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        max2 = nums[i];
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      }
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    }
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    return max1 >= 2 * max2 ? result : -1;
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  }
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};