How Many Numbers Are Smaller Than the Current Number LeetCode solution in JavaScript

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var smallerNumbersThanCurrent = function (nums) {
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  let count,
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    ans = [];
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  /*Run a loop on each element excluding nums[i]
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    and compare it with nums[j] if it's large, then count++
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    else break;*/
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  for (let i = 0; i < nums.length; i++) {
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    let temp = nums[i],
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      count = 0;
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    for (let j = 0; j < nums.length; j++) {
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      if (i === j) continue;
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      if (temp > nums[j]) count++;
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    }
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    ans.push(count);
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  }
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  return ans;
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};
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//second way using objects:--->
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var smallerNumbersThanCurrent = function (nums) {
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  let arr = [...nums],
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    ans = [];
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  arr.sort((a, b) => a - b);
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  let map = {};
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  map[arr[0]] = 0;
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  for (let i = 1; i < arr.length; i++) {
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    if (arr[i - 1] !== arr[i]) map[arr[i]] = i;
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  }
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  for (let i = 0; i < nums.length; i++) {
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    ans.push(map[nums[i]]);
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  }
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  return ans;
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};