How Many Numbers Are Smaller Than the Current Number LeetCode solution in C++

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class Solution {
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 public:
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  vector<int> smallerNumbersThanCurrent(vector<int> &nums) {
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    vector<int> ans;
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    int i, j, size, count;
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    size = nums.size();
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    for (i = 0; i < size; i++) {
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      count = 0;
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      for (j = 0; j < size; j++) {
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        if (nums[j] < nums[i]) count++;
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      }
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      ans.push_back(count);
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    }
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    return ans;
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  }
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};