HTML Entity Parser LeetCode solution in Python

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class Solution:
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    def entityParser(self, text: str) -> str:
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        d = {
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            """: '"',
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            "'": "'",
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            "&": "&",
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            ">": ">",
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            "&lt;": "<",
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            "&frasl;": "/",
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        }
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        ans = ""
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        i = 0
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        while i < len(text):
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            bag = ""
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            # condition if find & and next char is not & also and handdling index out of range for i + 1
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            if i + 1 < len(text) and text[i] == "&" and text[i + 1] != "&":
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                # create subtring for speacial char till ";"
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                for j in range(i, len(text)):
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                    if text[j] == ";":
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                        bag += text[j]
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                        break
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                    else:
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                        bag += text[j]
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                # if that not present in dict we added same as it is
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                if bag not in d:
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                    ans += bag
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                else:
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                    ans += d[bag]
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                # increment by length of bag
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                i += len(bag)
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            # otherwise increment by 1
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            else:
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                ans += text[i]
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                i += 1
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        return ans