Fizz Buzz LeetCode solution in JavaScript

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/**
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 * @param {number} n
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 * @return {string[]}
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 */
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var fizzBuzz = function (n) {
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  let arr = [];
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  for (let i = 1; i <= n; i++) {
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    if (i % 3 == 0 && i % 5 == 0) {
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      arr[i - 1] = "FizzBuzz";
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    } else if (i % 3 == 0 && i % 5 != 0) {
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      arr[i - 1] = "Fizz";
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    } else if (i % 3 != 0 && i % 5 == 0) {
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      arr[i - 1] = "Buzz";
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    } else {
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      arr[i - 1] = String(i);
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    }
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  }
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  return arr;
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};