Find Unique Binary String LeetCode solution in Python

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class Solution(object):
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def findDifferentBinaryString(self, nums):
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ans = ""
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for i, num in enumerate(nums):
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ans += "1" if (num[i] == "0") else "0" # ternary if else
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# ans+= str(1- int(num[i])); # Alternate: cast to string & 1-x to flip
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return ans

0

WPM •0 •0

100%

ACC •0 •0

0s

TIME •0