Find Pivot Index LeetCode solution in Python

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# Runtime: 342 ms (Top 15.25%) | Memory: 15.2 MB (Top 92.14%)
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class Solution:
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    def pivotIndex(self, nums: List[int]) -> int:
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        right = sum(nums)
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        left = 0
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        for i in range(len(nums)):
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            right -= nums[i]
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            left += nums[i - 1] if i > 0 else 0
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            if right == left:
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                return i
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        return -1