Find Pivot Index LeetCode solution in JavaScript
1/**2* @param {number[]} nums3* @return {number}4*/5var pivotIndex = function (nums) {6//step 17var tot = 0;8for (let i = 0; i < nums.length; i++) {9tot += nums[i];10}11// Step 212left = 0;13for (let j = 0; j < nums.length; j++) {14right = tot - nums[j] - left;15if (left == right) {16return j;17}18left += nums[j];19}20return -1;21};