Expressive Words LeetCode solution in JavaScript

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/**
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 * @param {string} s
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 * @param {string[]} words
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 * @return {number}
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 */
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var expressiveWords = function (s, words) {
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  let arr = [];
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  let curr = 0;
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  while (curr < s.length) {
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    let count = 1;
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    while (s[curr] === s[curr + 1]) {
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      count++;
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      curr++;
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    }
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    arr.push([s[curr], count]);
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    curr++;
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  }
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  let ans = 0;
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  for (let charArr of words) {
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    let idx = 0;
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    let i = 0;
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    let flag = true;
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    if (charArr.length > s.length) continue;
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    while (i < charArr.length) {
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      let count = 1;
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      while (charArr[i] === charArr[i + 1]) {
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        i++;
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        count++;
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      }
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      if (
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        arr[idx][0] !== charArr[i] ||
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        arr[idx][1] < count ||
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        (arr[idx][1] < 3 && arr[idx][1] !== count)
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      ) {
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        flag = false;
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        break;
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      }
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      idx++;
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      i++;
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    }
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    if (idx !== arr.length) flag = false;
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    if (flag) ans++;
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  }
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  return ans;
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};